Object projected vertically upwards 1. Maximum height reached (H) = ˝ gt^{2} = u^{2}/2g 2. At any other height except the maximum: h = ut +˝gt^{2}space v^{2} = u^{2} +2gh spa where g = - 9.8 ms^{-2} |
Object projected horizontally The horizontal distance travelled (s) = horizontal velocity x time = v_{x}t = ut The vertical distance travelled (h) = u_{y}t + ˝ (gt^{2}) = ˝ (gt^{2}) since u_{y} = 0 Velocity after a time t: space v = (v_{x}^{2} + v_{y}^{2})^{1/2} Direction of motion after time t: space tanq = v_{y}/v_{x} Equation for the path: spaceh = ˝ (gt^{2}) = ˝ (gs^{2}/u^{2}) = s^{2}( ˝ )(g/u^{2}) |